2-E
𝑝 = (0.5).
n = (s, t)
s = (1) *repeated a nsu amount of times which is 0.5)
t = (1, ∞)
𝑝 = (0.5) = (1 repeated a 0.5 of times, 1 where the growth is ∞/Planck Time.)
2-D
𝑝 = (1).
n = (s, t)
s = (1) *repeated a nsu amount of times which is 1)
t = (1, 0)
𝑝 = (1) = (1 repeated a total of 1times, 1 where the growth is ∞/Planck Time.)
3-D
EDIT: ***ASSUMING nm > m and lim = cm. in simpler terms, what qualifies for Multiverse, not Low Multiverse***
𝑝 = (r)
n = (s, t)
s = (nm) *repeated a nsu amount of times which is r)
t = (1, 0)
𝑝 = (1) = (1 repeated a total of 1times, 1 where the growth is 0/Planck Time.)
Calculation for the growth:
Δt / Δd
1 / 1
growth = 0
𝑝 = (0.5).
n = (s, t)
s = (1) *repeated a nsu amount of times which is 0.5)
t = (1, ∞)
𝑝 = (0.5) = (1 repeated a 0.5 of times, 1 where the growth is ∞/Planck Time.)
𝑓′(𝑥)=𝑓(𝑥+ℎ)−𝑓(𝑥) / ℎ
𝑓′(𝑥)=𝑓(𝑥+ ∞)−𝑓(𝑥) / ∞
𝑓′(𝑥)=∞ / ∞
Therefore, growth = ∞
𝑝 = (1).
n = (s, t)
s = (1) *repeated a nsu amount of times which is 1)
t = (1, 0)
𝑝 = (1) = (1 repeated a total of 1times, 1 where the growth is ∞/Planck Time.)
𝑓′(𝑥)=𝑓(𝑥+ℎ)−𝑓(𝑥) / ℎ
𝑓′(𝑥)=𝑓(𝑥+ ∞)−𝑓(𝑥) / ∞
𝑓′(𝑥)=∞ / ∞
Therefore, growth = ∞
EDIT: ***ASSUMING nm > m and lim = cm. in simpler terms, what qualifies for Multiverse, not Low Multiverse***
𝑝 = (r)
n = (s, t)
s = (nm) *repeated a nsu amount of times which is r)
t = (1, 0)
𝑝 = (1) = (1 repeated a total of 1times, 1 where the growth is 0/Planck Time.)
Calculation for the growth:
Δt / Δd
1 / 1
growth = 0